In a different angular analysis involving an angle of 4 degrees, what are the base angles of the isosceles triangle?

To find the base angles of an isosceles triangle when given the vertex angle, we start with a key property of triangles: the sum of all interior angles in any triangle is always 180 degrees.

In the case of an isosceles triangle, two angles are equal (the base angles), and one angle is different (the vertex angle). If the vertex angle is given as 4 degrees, we can calculate the base angles as follows:

1. First, subtract the vertex angle from the total sum of interior angles: [ 180 - 4 = 176 \text{ degrees} ]

2. Since the two base angles are equal, we divide this result by 2 to find each base angle: [ \frac{176}{2} = 88 \text{ degrees} ]

Therefore, each base angle measures 88 degrees. This solution confirms that option B is the correct answer, as it reflects the calculated measure of each base angle in the isosceles triangle based on the given vertex angle of 4 degrees.